y`=2·(1/x)`+3·(x3/4)`–2·(x7)`–3·(sinx)`+2·(arccosx)`= =2·(–1/x2)+3·(3/4)·x(3/4)–1 –2·7x6–3·cosx+2·(–1/√1–x2)= =(–2/x2)+ 9/(4x1/4)–14x6 3cosx–2/√1–x2.