Задача 31325 1. sin(3x/2) = sqrt(2)/2 2. tg(2x-Pi/3)...

bilikto555

2018-11-27 14:23:10

1. sin(3x/2) = sqrt(2)/2

2. tg(2x-Pi/3) = -5

sova

2018-11-27 14:48:02

★

(3x/2)=(-1)^(k)arcsin(sqrt(2)/2)+πk, k ∈ Z
x=(-1)^(k)*(2/3)*(π/4)+(2/3)πk, k ∈ Z
[b]x=(-1)^(k)(π/6)+(2/3)πk, k ∈ Z[/b]

2.
(2x-(π/3))=arctg(-5)+πn, n ∈ Z
2x=(π/3)-arctg5+πn, n ∈ Z
[b]x=(π/6)-(1/2)*arctg5+(π/2)*n, n ∈ Z[/b]