cos2x+sin^2x = 3/4, [Pi; 2,5Pi] sin(Pi/2+x) = sin2x, [-Pi; Pi/2] cos2x-5sqrt(2)cosx-5 = 0, [-3Pi; -3Pi/2]
Решить уравнения: 1) cos^23x-sin^23x = 0 2) sinxcosx = sqrt(3)/4 3) 5sin^2x+sinx-6 = 0 4) 1-cos2x = 2sinx 5) 5sin^2x+6cosx-6 = 0