cos2x+sin2x = 3/4, [π; 2,5π] sin(π/2+x) = sin2x, [–π; π/2] cos2x–5√2cosx–5 = 0, [–3π; –3π/2]
Решить уравнения: 1) cos23x–sin23x = 0 2) sinxcosx = √3/4 3) 5sin2x+sinx–6 = 0 4) 1–cos2x = 2sinx 5) 5sin2x+6cosx–6 = 0