x= ρ ·cos φ
y= ρ ·sin φ
x2+ y2= R 2
(ρ ·cos φ )2+( ρ ·sin φ )2= R 2
так как cos2 φ +sin2 φ =1,
то
ρ2= R 2
1.
х = —1,
ρ ·cos φ =–1
⇒
ρ =–1/cos φ
2.
у=8,
ρ ·sin φ =8
⇒
ρ =8/sin φ
3.
у+х = –3,
ρ ·sin φ+ ρ ·cos φ =–3
ρ =–3/(sin φ +cos φ )
4.
х2+ у2 = 10,
⇒ ρ 2=10
ρ =√10
5.
х2 + у2 =х,
ρ 2= ρ ·cos φ
ρ =cos φ
6
х2+ у2= —2у
ρ 2=–2· ρ ·sin φ
ρ =–2sin φ