π/4 ∫ (1 + 5tgx)/cos² x dx π/6
[m]=(tgx+5\frac{tg^2x}{2})|∫_{\frac{π}{6}} ^{\frac{π}{4}}=tg\frac{π}{4}+\frac{5}{2}tg^2\frac{π}{4}-tg\frac{π}{6}-\frac{5}{2}tg^2\frac{π}{6}=[/m]
[m]=1+\frac{5}{2}-\frac{\sqrt{3}}{3}-\frac{5}{2}\cdot (\frac{\sqrt{3}}{3})^2=[/m]