Вычислите неопределенные интегралы 4. ∫ (5x + 3)³ dx
[m] d(5x+3)=(5x+3)`dx=5dx[/m] ⇒ [m]dx=\frac{1}{5}d(5x+3)[/m] [m]∫ (5x+3)^3dx=∫ (5x+3)^3\cdot \frac{1}{5}d(5x+3)=\frac{1}{5} ∫(5x+3)^3d(5x+3) =\frac{1}{5}\cdot \frac{(5x+3)^4}{4}+C=\frac{(5x+3)^4}{20}+C[/m]