arccos(-sqrt(2)/2)=3π/4 так как cos (3π/4)=- sqrt(2)/2 и (3π/4) ∈ [b][0; π][/b] arcctg(-sqrt(3))=5π/6 так как tg (5π/6)=-sqrt(3) и (5π/6) ∈[b] [0; π][/b] О т в е т. (3π/4)+2*(5π/6)=(3π/4)+(5π/3)=...