Задача 48622 ...

sova

2020-04-27 21:01:02

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arcsin(sqrt(3)/2)=π/3

так как sin (π/3)=sqrt(3)/2 и (π/3) ∈ [-π/2; π/2]

arctg(-1)=-π/4
так как tg (-π/4)=-1 и (-π/4) ∈ [-π/2; π/2]

О т в е т. (π/3)+2*(-π/4)=(π/3)-(π/2)=