y=2x+2-x^2
x^2-2x-4=2x+2-x^2
2x^2-4x-6=0
x^2-2x-3=0
D=16
x_(1)=-1; x_(2)=3
S= ∫ ^(b)_(a)(f(x)-g(x)dx
S=∫ ^(3)_(-1)(2x+2-x^2-(x^2-2x-4))dx=
=∫ ^(3)_(-1)(6+4x-2x^2)dx=(6x+2x^2-(2/3)x^3)|^(3)_(-1)=
=6*(3-(-1))+2*(3^2-(-1)^2)-(2/3)*(3^3-(-1)^3)=
=24+16-(2/3)*28=[b]64/3[/b]