[m]\frac{7cos\alpha-6sin\alpha}{3sin\alpha+2cos\alpha}=\frac{\frac{7cos\alpha-6sin\alpha}{cos\alpha}}{\frac{3sin\alpha+2cos\alpha}{cos\alpha}}[/m]
Получим:
[m]\frac{7-6tg α}{3tg α +2}[/m]
при tg α =3
О т в е т. [m]\frac{7-6\cdot 3}{3\cdot 3+2}=-\frac{11}{11}=-1[/m]