Поэтому
[m](e^{i\frac{\pi}{3}})^{4}=e^{i\frac{4\pi}{3}}=[/m]
[m]=cos\frac{4\pi}{3} +isin\frac{4\pi}{3}=\frac{(-\sqrt{3})}{2}+i\frac {(-1)}{2}[/m]
[m]cos\frac{\pi}{2} +isin\frac{\pi}{2}=0+i=i[/m]
[m](e^{i\frac{\pi}{3}})^{4}\cdot (cos\frac{\pi}{2} +isin\frac{\pi}{2})=[/m]
[m]=(\frac{(-\sqrt{3})}{2}+i\frac {(-1)}{2})\cdot i=\frac {1}{2}-i\frac{\sqrt{3}}{2}[/m]