z=x+iy
z=x–iy
z2=(x+iy)2
z2·i·z=(x+iy)2·i·(x–iy)=(x+iy)·(x–iy)·(xi+i2y)=
=(x2+y2)·(xi–y)=–y(x2+y2)+i·x·(x2+y2)
Im(z2·i·z)=x·(x2+y2)=x3+xy2
2.
z=(2i+1)(1–2i)2+i·(2+3i)=
=(1–(2i)2)·(1–2i)+2i+3i2=
=(1+4)·(1–2i)+2i–3=
=5–10i+2i–3=
=2–8i
О т в е т. y=–8