y=4-x^2,y=0,x=0,где x>=0 вокруг оси оX
V_(ох)=π ∫^(2)_(0)(4-x^2)^2dx=π ∫^(2)_(0)(16-8x^2+x^4)dx= =π(16x-(8x^3/3)+(x^5/5))|^(2)_(0)=π(16*2-(8*8/3)+(32/5))=