log(2x+1) (4x-5) + log(4x-5)(2x+1) ≤ 2
{4x-5>0⇒ x>5/4
{2x+1>0⇒ x>-1/2
{2x+1≠ 1⇒ x≠0
{4x-5≠ 1⇒ x≠3/2
x ∈ (5/4;3/2)U(3/2;+∞ )
log_(2x+1)(4x-5)=t
log_(4x-5)(2x+1)=1/t
t+(1/t) ≤ 2 ⇒
(t^2-2t+1)/t ≤ 0
t=1 или t < 0
log_(2x+1)(4x-5)=1
2x+1=4x-5
2x=6
x=3
log_(2x+1)(4x-5)<0
(2x+1-1)*(4x-5-1) <0
2x*(4x-6) <0
___ (0) __-_ (3/2)
0 < x < 3/2
C учетом ОДЗ
О т в е т. (5/4; 3/2) U {3}