y = x2+2x; y = x+2
x2+2x=x+2
x2+x–2=0
D=1+8=9
x1=(–1–3)/2= – 2 или х2=(–1+3)/2=1
S=∫1–2(x+2–(x2+2x))dx= ∫1–2(2–x2– x)dx=
=(2x–(x3/3)–(x2/2))|1–2=
=2·(1–(–2)) – ((1/3)–(–8/3))–((1/2)–(4/2))=
=6–3+1,5=4,5
см. рис.