vector{a}×vector{b}=(3vector{p}+vector{q})×(vector{p}-3vector{q})=
= применяем законы векторной [b]алгебры[/b]=
=3vector{p}×(vector{p}+vector{q})×vector{p} -9*vector{p}×vector{q}-3vector{q}×vector{q}
Так как
vector{p}×(vector{p}=0
vector{q})×vector{p} = - vector{p}×vector{q}
vector{q}×vector{q}=0
vector{a}×vector{b}=10vector{p}×vector{q}= 10*|vector{p}|*|vector{q}|*sin ∠(vector{p},vector{q})=10*7*2*sin( π/4)=70sqrt(2)
S( параллелограмма)=70sqrt(20)