[block](sin4x)/(cos4x-1) = 0[/block]
{2cosx+sqrt(2)=0
{2sinx+sqrt(2) ≠ 0
{cosx=-sqrt(2)/2;
{sinx ≠ -sqrt(2)/2
О т в е т. х=(3π/4)+2πn, n ∈ Z
6.
{sin4x=0
{cos4x-1 ≠ 0
{sin4x=0
{cos4x ≠ 1
{4x=πk, k ∈ Z
{4x ≠ 2πn, n ∈ Z
{x=(π/4)*k, k ∈ Z
{x ≠ (π/2)*n, n ∈ Z
(π/4)*k ≠ (π/2)*n
k/4≠n/2
k≠2n
О т в е т. ± (π/4)+πm, m ∈ Z
см. рис.