1)
{4x–7 ≥ 0
{logx2–4x+5(3x–5) ≥ 0
или
2){4x–7 ≤ 0
{logx2–4x+5(3x–5) ≤ 0
1)
{ х ≥ 7/4
{x2–4x+5 > 0; x2–4x+5 ≠ 1⇒ x ≠2
{3x–5 > 0 ⇒ x > 5/3
{(x2–4x+5–1)·(3x–5–1) ≥ 0 ⇒ 3(x–2)3 ≥ 0 ⇒ x ≥ 2
о т в е т. 1) (2;+ ∞ )
ИЛИ
2)
2){x ≤ 7/4
{x2–4x+5 > 0; x2–4x+5 ≠ 1⇒ x ≠2
{3x–5 > 0 ⇒ x > 5/3
{(x2–4x+5–1)·(3x–5–1) ≤ 0 ⇒ 3(x–2)3 ≤ 0 ⇒ x ≤ 2
о т в е т. 2) (5/3; 7/4]
Объединяем ответ 1) и ответ 2)
О т в е т.(5/3; 7/4] U (2;+ ∞ )