Задача 80560 реши 19...

691fdd55a0211e4a1fadbd5e

11/21/2025 3:37:45 AM

реши 19

626fab9a354ab65fb2f43abb

11/21/2025 8:10:40 AM

★

19. z1 = 5 + 3i; z2 = 2 + i
z1 + z2 = 5 + 3i + 2 + i = (5+2) + (3i+i) = 7 + 4i
z1 - z2 = 5 + 3i - (2 + i) = (5-2) + (3i - i) = 3 + 2i
z1*z2 = (5 + 3i)(2 + i) = 5*2+3i*2+5*i+3i*i = 10+6i+5i-3 = 7 + 11i
[m]\large \frac{z1}{z2} = \frac{5+3i}{2+i} = \frac{(5+3i)(2-i)}{(2+i)(2-i)} = \frac{10+6i-5i+3}{4+1} = \frac{13+i}{5} = \frac{13}{5}+\frac{i}{5}[/m]