Задача 78853 найти значение функции в точке x0...
Условие
математика 10-11 класс
109
Решение
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[m]\large f(x0) = f(4) = 4^{-\frac{1}{2}} = \frac{1}{4^{\frac{1}{2}}} = \frac{1}{\sqrt{4}} = \frac{1}{2}[/m]
б) [m] \large f(x) = x^{\frac{3}{2}}; x0 = 4[/m]
[m]\large f(x0) = f(4) = 4^{\frac{3}{2}} = \sqrt{4^3} = (\sqrt{4})^3 = 2^3 = 8[/m]
в) [m] \large f(x) = x^{\frac{5}{3}}; x0 = 8[/m]
[m]\large f(x0) = f(8) = 8^{\frac{5}{3}} = \sqrt[3]{8^5} = (\sqrt[3]{8})^5 = 2^5 = 32[/m]
г) [m] \large f(x) = x^{\frac{3}{4}}; x0 = 16[/m]
[m]\large f(x0) = f(16) = 16^{\frac{3}{4}} = \sqrt[4]{16^3} = (\sqrt[4]{16})^3 = 2^3 = 8[/m]