3
????
+
1
????
+
4
−
????
−
1
????
−
4
=
3
x+4
3x+1
−
x−4
x−1
=3.
3x2+x–12x–4–(x2–x+4x–4)=3(x2–16),
3x2–11x–4–x2–3x+4=3x2–48,
x2+14x–48=0,
D/4=49+48=97=(√97)2,
x=(–7 ± √97)/1,
x1=–7–√97, x2=–7+√97.
Находим среднее арифметическое:
(x1+x2)/2=(–7–√97–7+√97)/2=–7.
Ответ: –7.