Задача 77355 [m]\frac{x}{4}+\frac{1}{12}=\frac{3x+1}{2}-\frac{2}{9}[/m]...

6610e13ca4fded5f0eff603b

5/7/2024 3:34:06 PM

[m]\frac{x}{4}+\frac{1}{12}=\frac{3x+1}{2}-\frac{2}{9}[/m]

5f3ea7e3faf909182968ddd9

5/7/2024 7:48:48 PM

★

[m]\frac{x}{4}+\frac{1}{12}=\frac{3x+1}{2}-\frac{2}{9}[/m]

[m]\frac{3x}{12}+\frac{1}{12}=\frac{9(3x+1)}{18}-\frac{4}{18}[/m]

[m]\frac{3x+1}{12}=\frac{9(3x+1)-4}{18}[/m]

Умножаем обе части на 36

[m]36\cdot \frac{3x+1}{12}=36\cdot \frac{9(3x+1)-4}{18}[/m]

3*(3x+1)=2*(9(3x+1)-4)

9x+3=54x+18-8

9x-54x=18-8-3

-45x=7

x=-7/45