Найдите значение f(4) + 1/3.
f(x)=ax^(2)+bx+c,
{a+b+c=-7/3,
{25a+5b+c=-7/3,
{9a+3b+c=-1;
{-24a-4b=0,
{c=-1-9a-3b,
{a+b+c=-7/3;
{b=-6a,
{c=-1+9a,
{a-6a-1+9a=-7/3;
{b=-6a,
{c=-1+9a,
{a=-1/3;
{b=2,
{c=-4,
{a=-1/3;
f(x)=(-1/3)x^(2)+2x-4,
f(4)+(1/3)=(-16/3)+8-4+(1/3)=-5+8-4=-1.