{(2/x)+1>0,
{32x-1>0,
{((2/x)-1)((2/x+1)) ≤ 32x-1;
{(2-x)/x>0,
{(2+x)/x>0,
{x>1/32,
{(4/x^(2))-1 ≤ 32x-1;
{(x-2)/x<0,
{(x+2)/x>0,
{x>1/32,
{(4/x^(2))-32x ≤ 0;
{0<x<2,
{x<-2 или x>0,
{x>1/32,
{(4-32x^(3))/x^(2) ≤ 0;
{(1/32)<x<2,
4-32x^(3) ≤ 0;
{(1/32)<x<2,
{x^(3)-(1/8) ≥ 0;
{(1/32)<x<2,
{(x-(1/2))(x^(2)+(1/2)x+(1/4)) ≥ 0;
так как x^(2)+(1/2)x+(1/4)>0 при любом х, то:
{(1/32)<x<2,
{x-(1/2) ≥ 0;
{(1/32)<x<2,
{x ≥ 1/2;
(1/2) ≤ x<2,
x ∈ [1/2; 2).
Ответ: [1/2; 2).