Задача 75633 ...

632f635587d19127bff140f0

1/31/2024 7:56:58 PM

Упростите выражение:
sin(π + α) cos(2π/2 - α) tg(α - π/2) / cos(π/2 + α) cos(3π/2 + α) tg(π + α)

626fab9a354ab65fb2f43abb

1/31/2024 8:22:20 PM

★

[m]\frac{sin(\pi+a)cos(2\pi/2-a)tg(a-\pi/2)}{cos(\pi/2+a)cos(2\pi/2+a)tg(\pi+a)} = \frac{-sin(a)(-cos(a))(-ctg(a))}{-sin(a)(-cos(a))tg(a)} =-\frac{ctg(a)}{tg(a)} = -\frac{1}{tg^2(a)}[/m]