Задача 75310 782. Обчисліть: 1)...
Условие
1) 7\frac{14}{15}+2\frac{1}{15};
2) 9\frac{24}{27}+12\frac{13}{27};
7) 13\frac{4}{9}-2\frac{8}{9};
4) 8-3\frac{6}{15};
8) 10\frac{7}{16}-4\frac{12}{16};
4) \frac{34}{39}-\frac{15}{39}-\frac{8}{39}.
3) \frac{15}{17}-(b-\frac{3}{17})=\frac{6}{17};
4) \frac{29}{43}-(m+\frac{13}{43})=\frac{5}{43}.
5) 12-11\frac{6}{11};
6) 16\frac{3}{13}-6\frac{8}{13};
9) 29\frac{49}{53}-8\frac{49}{53}.
3) 1-\frac{12}{19};
Решение
748
4)
[m] \frac{34}{39}–\frac{15}{39}–\frac{8}{39}=\frac{34-15-8}{39}=\frac{11}{39}[/m].
756
3)
[m] \frac{15}{17}–(b–\frac{3}{17})=\frac{6}{17}[/m]
[m](b–\frac{3}{17})= \frac{15}{17}-\frac{6}{17}[/m]
[m]b=\frac{3}{17}+ \frac{9}{17}[/m]
[m]b=\frac{3+9}{17}[/m]
[m]b=\frac{12}{17}[/m]
4)
[m] \frac{29}{43}–(m+\frac{13}{43})=\frac{5}{43}[/m]
[m](m+\frac{13}{43})= \frac{29}{43}–\frac{5}{43}[/m]
[m]m+\frac{13}{43}= \frac{24}{43}[/m]
[m]m= \frac{24}{43}-\frac{13}{43})[/m]
[m]m= \frac{11}{43}[/m]
782
1)[m]7\frac{14}{15}+2\frac{1}{15}=(7+2)+\frac{14}{15}+\frac{1}{15}=9+\frac{15}{15}=9+1=10[/m]
2)[m] 9\frac{24}{27}+12\frac{13}{27}=(9+12)+(\frac{24}{27}+1\frac{13}{27})=21+\frac{41}{27}=21+1\frac{14}{27}=22\frac{14}{27}[/m]
3)[m] 1–\frac{12}{19}=\frac{19}{19}-\frac{12}{19}=\frac{19-12}{19}=\frac{7}{19} [/m]
4)[m] 8–3\frac{6}{15}=7\frac{15}{15}-3\frac{6}{15}=(7-3)+\frac{15-6}{15}=4\frac{9}{15}=4\frac{3}{5}[/m]
5)[m] 12–11\frac{6}{11}=11\frac{11}{11}-11\frac{6}{11}=(11-1)+\frac{11-6}{11}=\frac{5}{11}[/m]
6) [m]16\frac{3}{13}–6\frac{8}{13}=15\frac{16}{13}-6\frac{8}{13}=(15-6)+\frac{16-8}{13}=9\frac{8}{13}[/m]
7) [m]13\frac{4}{9}–2\frac{8}{9}=12\frac{13}{9}–2\frac{8}{9}=(12-2)+(\frac{13}{9}–\frac{8}{9})=10\frac{5}{9}[/m]
8)[m] 10\frac{7}{16}–4\frac{12}{16}= 9\frac{23}{16}–4\frac{12}{16}=5\frac{11}{16}[/m]
9)[m] 29\frac{49}{53}–8\frac{49}{53}=29-8=21[/m]