[m]5^2\cdot (\frac{1}{5})^{x^2-4x}>\frac{1}{125}[/m]
[m](\frac{1}{5})^{-2}\cdot (\frac{1}{5})^{x^2-4x}>(\frac{1}{5})^3[/m]
[m] (\frac{1}{5})^{x^2-4x-2}>(\frac{1}{5})^3[/m]
Показательная функция с основанием [m]0<\frac{1}{5}<1[/m] [i]убывающая[/i]
[m]x^2-4x-2<3[/m]
[m]x^2-4x-5<0[/m]
D=16+20=36
x_(1)=-1; x_(2)=5
[b]-1 < x< 5[/b]