Задача 72008 a=12 3 5 a hat 6 = 19 2/7 * ac = 23 5/8...

6486bc88fb2b923089102dc2

12.06.2023 09:38:18

a=12 3 5 a hat 6 = 19 2/7 * ac = 23 5/8 * a * (5as - 2v - 7) |

5f3ea7e3faf909182968ddd9

12.06.2023 12:10:40

★

[m]a=12\frac{3}{5}=\frac{63}{5}[/m]

[m]b=19\frac{2}{7}=\frac{155}{7}[/m]

[m]c=23\frac{5}{8}=\frac{189}{8}[/m]

S_(п п)=2ab+2ac+2bc=2(ab+ac+bc)=

=2*([m]\frac{63}{5}\cdot \frac{155}{7}+\frac{63}{5}\cdot \frac{189}{8}+\frac{155}{7}\cdot \frac{189}{8})=2\cdot \frac{63\cdot 155\cdot 8+63\cdot 189\cdot 7+155\cdot 189\cdot 5}{5\cdot 7\cdot 8}=2\cdot \frac{78120=83349+146476}{280}=\frac{307945}{140}=2199\frac{85}{140}=2199\frac{17}{28}[/m]


V=a*b*c=[m]\frac{63}{5}\cdot \frac{155}{7}\cdot \frac{189}{8}=\frac{1845585}{280}=6591\frac{375}{1000}=6591\frac{3}{8}[/m]