(5x-y)²/2y-10x
[m]\frac{(5x-y)^2}{2y-10x} =\frac{(y-5x)^2}{2(y-5x)}=\frac{y-5x}{2}[/m]
=(5х–у)^2/–2(–у+5х)= у–5х/2 Ответ: у–5х/2