log1/2(x^2-5x-6) =-3
x^(2)–5x–6=(1/2)^(-3) x^(2)–5x–6=2^(3) x^(2)–5x–6=8 x^(2)–5x–14=0 x1=7, x2=-2 ОДЗ: x^(2)–5x–6>0 x1=6, x2=-1 x ∈ (- ∝ ;-1) ∪ (6;+ ∝ ) Ответ: -2;7.