Найдите вторую производную функции: а) y=4sqrt(3x + 8); б) y=5x^5+3x^3
a) [m]y = 4\sqrt{3x+8}[/m] [m]y' = \frac{4}{2\sqrt{3x+8}}*3 = \frac{6}{\sqrt{3x+8}} = 6(3x+8)^{-1/2}[/m] [m]y'' = 6(-1/2)(3x+8)^{-3/2}*3 = -\frac{9}{(3x+8)^{3/2}}[/m] b) y = 5x^5 + 3x^3 y' = 5*5x^4 + 3*3x^2 = 25x^4 + 9x^2 y'' = 25*4x^3 + 9*2x = 100x^3 + 18x