Решение методом интервалов (x – 4)3(x – 5)4(x – 6)5 >= 0.
(x–4)3(x–5)4(x–6)5=0 x=4 x=5 x=6 ___+___ [4] ___–___[5] __–___[6]___+__ О т в е т. (– ∞ ;4]U{5}U[6;+ ∞ )