Дано y = 2/(x-6), dy=0.025, x=4. Найти Δx.
[m]f`(x)=(\frac{2}{x-6})`[/m] [m]f`(x)=-\frac{2}{(x-6)^2}[/m] [m]dy=f`(x)dx[/m] [m]dy(x_{o})=f`(x_{o}) Δx[/m] [m]0,025=-\frac{2}{(4-6)^2}Δx[/m] ⇒ [m]Δx=-0,05[/m]