Решите систему уравнений 2ху–3х..
0,5log_{6}\frac{9x-x^3-36}{5-y}=1-log_{36}(x-2)
log_{6}\frac{9x-x^3-36}{5-y}=2-2\cdot log_{6^2}(x-2)
log_{6}\frac{9x-x^3-36}{5-y}=log_{6}36-2\cdot\frac{1}{2} log_{6}(x-2)
log_{6}\frac{9x-x^3-36}{5-y}=log_{6}\frac{36}{x-2}
\left\{\begin {matrix}\frac{2xy-3x}{y-3}=2x+3\\\frac{9x-x^3-36}{5-y}>0\\x-2>0\\\frac{9x-x^3-36}{5-y}=\frac{36}{x-2}\end {matrix}\right.