{4x–3y=16
\left\{\begin{matrix}\frac{16+3y}{4}\cdot y=80\\ x=\frac{16+3y}{4}\end{matrix}\right. \left\{\begin{matrix}3y^2+16y-320=0\\ x=\frac{16+3y}{4}\end{matrix}\right.
D=256+3840=4096=642
\left\{\begin{matrix}
y_{1}=8\\ x_{1}=10\end{matrix}\right. или\left\{\begin{matrix}
y_{2}=-\frac{40}{3}\\ x_{2}=-6\end{matrix}\right.