[m](\frac{1}{3})^{-2}\cdot 27^{\frac{1}{3}}-\sqrt{81}+0,19^{0}=(3^{-1})^{-2}\cdot (3^{3})^{\frac{1}{3}}-9+1=[/m] [m]3^{2}\cdot 3-9+1=27-9+1=19[/m]
