= ∫ ^(1)_(0)(4x+3x^2)*(y^2/2)|^(x^2)_(-sqrt(x))dx=
= ∫ ^(1)_(0)((4x+3x^2)*(x^4/4)-(4x+3x^2)*(x/2))dx=
= ∫^(1)_(0)(x^5+(3/4)x^6-2x^2-3x^3/2)dx=
=((x^6/6)+(3/4)*(x^7/7)-(2x^3/3)-(3x^4/8))|^(1)_(0)=
=(1/6)+(3/28)-(2/3)-(3/4)=(3/28)-(5/4)=-32/28=-8/7