1. ∫(x dx)/(5 - 3x^2)^7
u=5-3x^2 du=d(5-3x^2)=(5-3x^2)`dx=-6xdx xdx=(-1/6)d(5-3x^2) ∫ (-1/6)*(5-3x^2)^(-7)d(5-3x^2)=(-1/6)*(5-3x^2)^(-7+1)/(-7+1)= =(1/36)*(1/(5-3x^2)^6)+C