√(4√2–7)²+4√2
Объяснение. √(4√2–7)²+4√2= ( т.к (4√2–7)²=(7–4√2)²) = =√(7–4√2)²+4√2= =|7–4√2|+4√2= ( т.к. 7–4√2=√49–√32>0 , то |7–4√2|=7–4√2 )= =7–4√2+4√2=7