(1;3) ⇒ x=1; F(1)=3
3=[m]\frac{1}{\sqrt{3}}+\frac{1^3}{3}+\frac{1^4}{4}+C[/m]
[m]C=3- \frac{1}{\sqrt{3}}-\frac{1}{3}-\frac{1}{4}[/m]
[m]C=\frac{3\cdot 12-3-4}{12}- \frac{\sqrt{3}}{3}[/m]
[m]C=\frac{29}{12}- \frac{\sqrt{3}}{3}[/m]
[m]C=\frac{29-4\sqrt{3}}{12}[/m]
О т в е т.
F(x)=[m]\frac{x}{\sqrt{3}}+\frac{x^3}{3}+\frac{x^4}{4}+\frac{29-4\sqrt{3}}{12}[/m]
F(x)=[m]\frac{4\sqrt{3}x+4x^3+3x^4+(29-4\sqrt{3})}{12}[/m]
3=1/sqrt(3)+1/3+1/4+С,
С=3-7/12-1/sqrt(3),
С=29/12-1/sqrt(3).
F(х)=х/sqrt(3)+х³/3+х⁴/4+29/12-1/sqrt(3).