помогите пожалуйса
∫ ^( + ∞)_(1)xdx/((4x^2)^2-1)= =(1/8) ∫ ^( + ∞)_(1)(8xdx)/((4x^2)^2-1)= =(1/8) * (1/2) ln |(4x^2-1)/(4x^2+1)|^(+ ∞ )_(1)= =(1/16)lim_(x → ∞ )ln |(4x^2-1)/(4x^2+1)|-(1/16)ln (3/5)= =(1/16)*ln1-(1/16)*(3/5)=[b]-3/80[/b]