Задача 48519 ...

sova

2020-04-27 14:30:57

[m]\frac{1}{2}-\frac{1}{8}=\frac{4}{8}-\frac{1}{8}=\frac{3}{8}[/m]

[m](\frac{1}{2}-\frac{1}{8})^3=(\frac{3}{8})^3=\frac{27}{512}[/m]


[m]\frac{1}{3}-\frac{1}{4}=\frac{4}{12}-\frac{3}{12}=\frac{1}{12}[/m]

[m](\frac{1}{3}-\frac{1}{4})^2=(\frac{1}{12})^2=\frac{1}{144}[/m]


[m](\frac{3}{2})^2=\frac{9}{4}[/m]


[m]\frac{27}{512}:\frac{1}{144}=\frac{27}{512}\cdot 144=\frac{243}{32}[/m]


[m]\frac{243}{32}\cdot \frac{9}{4}=\frac{2187}{128}=17 \frac{11}{128}[/m]