cos70cos10+sin70sin10
------------------------------ =
sin50cos10+cos50sin10
cos70 ° cos10 ° +sin70 ° sin10 ° =cos(70 ° - 10 ° )=cos60 °
[r] sin α *cos β +cos α *sin β =sin( α + β )[/r]
sin50 ° cos10 ° +cos50 ° sin10 ° =sin60 °
сtg60 ° =sqrt(3)/3 - о т в е т
sin50cos10+cos50sin10=sin(50+10) sin60
[ sin/cos=tg; cos/sin=ctg ]