Задача 46767 Задание 9...

dhehhebe

2020-04-12 15:21:36

Задание 9

sova

2020-04-12 15:40:29

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Ответ. 3

[m]3^{\frac{1}{3}}\cdot 3^{\frac{1}{4}}=3^{\frac{1}{3}+\frac{1}{4}}=3^{\frac{7}{12}}[/m]

[m]\sqrt[12]{3}=3^{\frac{1}{12}}[/m]

[m]3^{\frac{7}{12}} :3^{\frac{1}{12}}=3^{\frac{7}{12}-\frac{1}{12}}
=3^{\frac{1}{2}}=\sqrt{3}[/m]

[m]\frac{3^{\frac{1}{3}}\cdot 3^{\frac{1}{4}}}{\sqrt[12]{3}}=(\sqrt{3})^2=3[/m]