Задача 46047 ...

marinichvika15

2020-04-05 20:10:10

tg^2 2x ≥ 1

sova

2020-04-05 20:24:15

★

tg2x ≤ -1 или tg2x ≥ 1

-(π/2)+πn <2x [b]≤ [/b]-(π/4)+πn или (π/4)+πk [b] ≤[/b] 2x < (π/2)+πn

-(π/4)+(π/2)*n <x [b]≤ [/b]-(π/8)+(π/2)*n или (π/8)+(π/2)*k [b]≤[/b] x < (π/4)+(π/2)*n, k, n ∈ Z