Задача 46044 ...

marinichvika15

2020-04-05 19:24:20

tgx/1-tg^2x ≥ - 1/2

sova

2020-04-05 19:39:12

★

По формуле

tg2 α =2tg α /(1-tg^2 α )


tg2x ≥ -1

-(π/4)+πn < 2x < (π/2)+πn, n ∈ Z

[b]-(π/8)+(π/2)*n < x < (π/4)+(π/2)*n, n ∈ Z[/b]