Задача 45069 ...

maruforzuev

2020-03-17 14:56:37

∫ cos²3xdx=

sova

2020-03-18 17:29:03

[m]cos^23x=\frac{1+cos6x}{2}[/m]

[m]\int cos^23xdx=\int \frac{1+cos6x}{2}dx=\frac{1}{2}x+\frac{1}{12}\cdot sin6x+C[/m]