[m]cos\frac{5\pi }{12}=cos (\frac{\pi }{2}-\frac{\pi }{12})=sin\frac{\pi }{12}[/m]
[m]\frac{1}{2} sin\frac{\pi }{12}cos\frac{5\pi }{12}-sin^2\frac{\pi }{3}=\frac{1}{2} sin\frac{\pi }{12}sin\frac{\pi }{12}-(sin\frac{\pi }{3})^2=\frac{1}{2} \frac{1}{2}\cdot \frac{1}{2} - (\frac{\sqrt{3}}{2})^2=0[/m]