Задача 43805 #5...

romcas

2020-01-29 15:20:55

#5

sova

2020-01-29 17:05:08

★

По формуле

sin2 α =2sin α *cos α


y=sin8x

y`=(cos8x)*(8x)`=8cos8x

y`(π/3)=8*cos(8π/3)=8*cos(2π+ (2π/3)=8*cos(2π/3)=8*(-1/2)=-4