Задача 43802 #2 ...

romcas

2020-01-29 15:18:45

#2

sova

2020-01-29 17:15:32

★

y`=(1/5)*(x^5)`-(16/3)*(x^3)`=(1/5)*5x^4-(16/3)*3x^2=[b]x^4-16x^2[/b]

y`(-1)=(-1)^4-16*(-1)^2=1-16=[b]-15[/b]